Fwd: [BUGS] BUG #14850: Implement optinal additinal parameter for 'justify' date/time function

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Fwd: [BUGS] BUG #14850: Implement optinal additinal parameter for 'justify' date/time function

kes-kes


-------- Пересылаемое сообщение--------
11.10.2017, 17:12, "Pavel Stehule" <[hidden email]>:

Hi

2017-10-11 12:35 GMT+02:00 <[hidden email]>:
The following bug has been logged on the website:

Bug reference:      14850
Logged by:          Eugen Konkov
Email address:      [hidden email]
PostgreSQL version: 10.0
Operating system:   Linux mint 18: Linux work 4.4.0-57-generic #78-Ubu
Description:

Hi. I try to do next math:

select extract( month from justify_days( timestamp '2016-01-31' +interval '1
month' -timestamp '2016-01-31') );
 date_part
-----------
         0
(1 row)

I expect `1` but get `0`. But here everything is right:

>Adjust interval so 30-day time periods are represented as months

https://www.postgresql.org/docs/9.6/static/functions-datetime.html

But with ability to setup justify date the math will be more sharp.

Please implement next feature:

select extract( month from justify_days( timestamp '2016-01-31' +interval '1
month' -timestamp '2016-01-31'), timestamp '2016-01-31' );
 date_part
-----------
         1
(1 row)

This is useful when I try to calculate how much month are left between
service start and end dates.

This is not the bug, so pgsql-hackers, pgsql-general are better places for this discussion

I am thinking so your request has sense, and should be registered in ToDo list https://wiki.postgresql.org/wiki/Todo

You can try to connect people from PostgreSQL Pro company for implementation.

Regards

Pavel


Thank you.


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-------- Конец пересылаемого сообщения --------
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Re: Fwd: [BUGS] BUG #14850: Implement optinal additinal parameter for 'justify' date/time function

Brian Dunavant
A 'month' is an abstract measurement of time.  Sometimes it's 29 days, 30, or 31.   You cannot say "I have 30 days, how many months is that?" because the answer is "it depends".

<date> - <date> gives you an interval in days.   In your example, you took Jan 31 2016 and added "1 month".  Postgres says "I know feb 2016 is 29 days" and did it automatically for you.   When you then subtracted Jan 31 2016, you now have "29 days".   Postgres can no longer say "that is 1 month" because you cannot go that direction.

You are also using extract(month from X) incorrectly if you want the number of months between any time period.   That will only return a value between 0 and 11.

It will also be difficult because you are starting from a random day in the month, making it hard to really know what you mean.  Postgres' age() function may be able to help you with 'months'.  

flpg=# select age( '2016-02-01'::timestamp, '2016-01-01'::timestamp );
  age
-------
 1 mon

flpg=# select age( '2016-02-29'::timestamp, '2016-01-31'::timestamp );
   age
---------
 29 days
(1 row)

flpg=# select age( '2016-03-01'::timestamp, '2016-01-31'::timestamp );
     age
-------------
 1 mon 1 day





On Thu, Oct 12, 2017 at 4:00 AM, KES <[hidden email]> wrote:


-------- Пересылаемое сообщение--------
11.10.2017, 17:12, "Pavel Stehule" <[hidden email]>:

Hi

2017-10-11 12:35 GMT+02:00 <[hidden email]>:
The following bug has been logged on the website:

Bug reference:      14850
Logged by:          Eugen Konkov
Email address:      [hidden email]
PostgreSQL version: 10.0
Operating system:   Linux mint 18: Linux work 4.4.0-57-generic #78-Ubu
Description:

Hi. I try to do next math:

select extract( month from justify_days( timestamp '2016-01-31' +interval '1
month' -timestamp '2016-01-31') );
 date_part
-----------
         0
(1 row)

I expect `1` but get `0`. But here everything is right:

>Adjust interval so 30-day time periods are represented as months

https://www.postgresql.org/docs/9.6/static/functions-datetime.html

But with ability to setup justify date the math will be more sharp.

Please implement next feature:

select extract( month from justify_days( timestamp '2016-01-31' +interval '1
month' -timestamp '2016-01-31'), timestamp '2016-01-31' );
 date_part
-----------
         1
(1 row)

This is useful when I try to calculate how much month are left between
service start and end dates.

This is not the bug, so pgsql-hackers, pgsql-general are better places for this discussion

I am thinking so your request has sense, and should be registered in ToDo list https://wiki.postgresql.org/wiki/Todo

You can try to connect people from PostgreSQL Pro company for implementation.

Regards

Pavel


Thank you.


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To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-bugs


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Re: Fwd: [BUGS] BUG #14850: Implement optinal additinal parameter for 'justify' date/time function

kes-kes
huh... how did I miss `age` function???
 
Thanks. I give me the idea. I will add 5days when the month of day is greater or equal to 28
 
select age( '2016-02-29'::date +'5days'::interval, '2016-01-31'::date+'5days'::interval );
  age  
-------
 1 mon
(1 row)
 
It seems resolves my issue
 
 


12.10.2017, 17:38, "Brian Dunavant" <[hidden email]>:
A 'month' is an abstract measurement of time.  Sometimes it's 29 days, 30, or 31.   You cannot say "I have 30 days, how many months is that?" because the answer is "it depends".

<date> - <date> gives you an interval in days.   In your example, you took Jan 31 2016 and added "1 month".  Postgres says "I know feb 2016 is 29 days" and did it automatically for you.   When you then subtracted Jan 31 2016, you now have "29 days".   Postgres can no longer say "that is 1 month" because you cannot go that direction.

You are also using extract(month from X) incorrectly if you want the number of months between any time period.   That will only return a value between 0 and 11.

It will also be difficult because you are starting from a random day in the month, making it hard to really know what you mean.  Postgres' age() function may be able to help you with 'months'.  

flpg=# select age( '2016-02-01'::timestamp, '2016-01-01'::timestamp );
  age
-------
 1 mon

flpg=# select age( '2016-02-29'::timestamp, '2016-01-31'::timestamp );
   age
---------
 29 days
(1 row)

flpg=# select age( '2016-03-01'::timestamp, '2016-01-31'::timestamp );
     age
-------------
 1 mon 1 day





On Thu, Oct 12, 2017 at 4:00 AM, KES <[hidden email]> wrote:


-------- Пересылаемое сообщение--------
11.10.2017, 17:12, "Pavel Stehule" <[hidden email]>:

Hi

2017-10-11 12:35 GMT+02:00 <[hidden email]>:
The following bug has been logged on the website:

Bug reference:      14850
Logged by:          Eugen Konkov
Email address:      [hidden email]
PostgreSQL version: 10.0
Operating system:   Linux mint 18: Linux work 4.4.0-57-generic #78-Ubu
Description:

Hi. I try to do next math:

select extract( month from justify_days( timestamp '2016-01-31' +interval '1
month' -timestamp '2016-01-31') );
 date_part
-----------
         0
(1 row)

I expect `1` but get `0`. But here everything is right:

>Adjust interval so 30-day time periods are represented as months

https://www.postgresql.org/docs/9.6/static/functions-datetime.html

But with ability to setup justify date the math will be more sharp.

Please implement next feature:

select extract( month from justify_days( timestamp '2016-01-31' +interval '1
month' -timestamp '2016-01-31'), timestamp '2016-01-31' );
 date_part
-----------
         1
(1 row)

This is useful when I try to calculate how much month are left between
service start and end dates.

This is not the bug, so pgsql-hackers, pgsql-general are better places for this discussion

I am thinking so your request has sense, and should be registered in ToDo list https://wiki.postgresql.org/wiki/Todo

You can try to connect people from PostgreSQL Pro company for implementation.

Regards

Pavel


Thank you.


--
Sent via pgsql-bugs mailing list ([hidden email])
To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-bugs


-------- Конец пересылаемого сообщения --------

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